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ACER 宏碁 白 UM08B31 6芯 日系電芯 電池 A110 A150 D150 D250 531h A110X AOD150 AOD250 UM08A73 UM08A74

功能
:

ACER 宏碁 白 UM08B31 6芯 日系電芯 電池 A110 A150 D150 D250 531h A110X AOD150 AOD250 UM08A73 UM08A74

描述
:


電池共用型號:

UM08A31 UM08A41 UM08A32 UM08A51 UM08A52 UM08A71 UM08A72 UM08A73 UM08A74 UM08B31 UM08B32 UM08B41 UM08B52 UM08B71 UM08B72 UM08B73 UM08B74 UM08B75

LC.BTP00.017 LC.BTP00.018

AR5BXB63 C-5448

適用筆電型號:

Acer Aspire ONE

A110 A110L A110X A150 A150L A150X D150 D250

P531 531 P531H 571 531F EM250 ZG5

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產品訊息

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電池類型鋰電池 / OEM
電池電壓11.1V
電池容量5200mAh
電池芯數6芯
電池顏色白色?
電池包裝獨立紙盒,防震海棉
電池保固三個月














ACER 宏碁 白 UM08B31 6芯 日系電芯 電池 A110 A150 D150 D250 531h A110X AOD150 AOD250 UM08A73 UM08A74





相關 ACER 宏碁 白 UM08B31 6芯 日系電芯 電池 A110 A150 D150 D250 531h A110X AOD150 AOD250 UM08A73 UM08A74

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標題:

程式設計(MATLAB)

發問:

A fenced enclosure consists of a rectangle of length L and width 2R, and a semicircleof radius R, as shown in Figure 2. The enclosure is to be built to have an area A of1600 feet2. The cost of the fence is $40 per foot for the curved portion, and $30 perfoot for the straight sides. Use fminbnd and constr... 顯示更多 A fenced enclosure consists of a rectangle of length L and width 2R, and a semicircle of radius R, as shown in Figure 2. The enclosure is to be built to have an area A of 1600 feet2. The cost of the fence is $40 per foot for the curved portion, and $30 per foot for the straight sides. Use fminbnd and constr functions to determine the values of R and L required to minimize the total cost of the fence. Also compute the minimum cost. Figure 2:http://i61.photobucket.com/albums/h45/a29211061/09.jpg 更新: 底下大大我沒說錯,的確用"constr"來解題!

最佳解答:

"constr" MATLAB沒有這的函數 你說的應該是 COST function 吧!? 2006-06-09 00:40:07 補充: 但是我以MATLAB ver.7版本 卻沒有 constr這個函數,而fminbnd就有。你要不要在確認一下呢! 2006-06-09 00:42:55 補充: 是constraint的縮寫嗎?! 2006-06-10 03:51:11 補充: 我還是認為"constr"這應該是你的筆誤 我猜題目的用意是求取一定面積下,所使用圍籬成本最低價錢 所以我計算如下 %%%%%%%%%%%%%%%%%%%%%%%%%% clc; low_R = 0; up_R = 100; fencedCost = @(R) ((2.*(1./(2.*R).*(1600 - pi./2.*R.^2))+2.*R).*30+pi.*R.*40); [minR, minCost] = fminbnd(fencedCost, low_R, up_R); minL = (1./(2.*minR).*(1600 - pi./2.*minR.^2)); disp('================================================================'); fprintf('The rectangle of min. length L is %7.3f ft The semicircle of min. radius R is %7.3f ft ',minL,minR); fprintf('Then we evaluate the minimized total cost of the fence is $%7.3f dollars ',minCost); %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% >> minL minL = 28.3599 >> minR minR = 18.6137 >> minCost minCost = 5.1575e+003 >> ================================================================ The rectangle of min. length L is 28.360 ft The semicircle of min. radius R is 18.614 ft Then we evaluate the minimized total cost of the fence is $5157.484 dollars >> 你認為呢!?

其他解答:

ACER 宏碁 白 UM08B31 6芯 日系電芯 電池 A110 A150 D150 D250 531h A110X AOD150 AOD250 UM08A73 UM08A74

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